import java.util.*; class VaultDoor1 { public static void main(String args[]) { VaultDoor1 vaultDoor = new VaultDoor1(); Scanner scanner = new Scanner(System.in); System.out.print("Enter vault password: "); String userInput = scanner.next(); String input = userInput.substring("picoCTF{".length(),userInput.length()-1); if (vaultDoor.checkPassword(input)) { System.out.println("Access granted."); } else { System.out.println("Access denied!"); } } // I came up with a more secure way to check the password without putting // the password itself in the source code. I think this is going to be // UNHACKABLE!! I hope Dr. Evil agrees... // // -Minion #8728 public boolean checkPassword(String password) { return password.length() == 32 && password.charAt(0) == 'd' && password.charAt(29) == 'a' && password.charAt(4) == 'r' && password.charAt(2) == '5' && password.charAt(23) == 'r' && password.charAt(3) == 'c' && password.charAt(17) == '4' && password.charAt(1) == '3' && password.charAt(7) == 'b' && password.charAt(10) == '_' && password.charAt(5) == '4' && password.charAt(9) == '3' && password.charAt(11) == 't' && password.charAt(15) == 'c' && password.charAt(8) == 'l' && password.charAt(12) == 'H' && password.charAt(20) == 'c' && password.charAt(14) == '_' && password.charAt(6) == 'm' && password.charAt(24) == '5' && password.charAt(18) == 'r' && password.charAt(13) == '3' && password.charAt(19) == '4' && password.charAt(21) == 'T' && password.charAt(16) == 'H' && password.charAt(27) == '6' && password.charAt(30) == 'f' && password.charAt(25) == '_' && password.charAt(22) == '3' && password.charAt(28) == 'd' && password.charAt(26) == 'f' && password.charAt(31) == '4'; } }d35cr4mbl3_tH3